If( PatternCount(info_Package,"C"), "32", "0")

I now have a calculation that will give me any given number if the field(info_package) contains a "C". Lets just say that that number is "32" ... Does anyone know what calc I can use for the following problem

I want it to double the number (32) if there are two "C"s in the field or triple of there are three of them

Any Suggestions?

Well,

PatternCount(Your field"C")

Lets call this field Count the C

Will return the number of C's in that field, for that record.

Then you can use a calculation

Count the C * 32

If it is only 1 C, you get 32,

2 gives 64, 3 gives 96 etc...etc...etc