Sorry ... one more time ....

[tallboy755]

If( PatternCount(info_Package,"C"), "32", "0")

I now have a calculation that will give me any given number if the field(info_package) contains a "C". Lets just say that that number is "32" ... Does anyone know what calc I can use for the following problem

I want it to double the number (32) if there are two "C"s in the field or triple of there are three of them

Any Suggestions?

[andygaunt]

Well,

PatternCount(Your field"C")

Lets call this field Count the C

Will return the number of C's in that field, for that record.

Then you can use a calculation

Count the C * 32

If it is only 1 C, you get 32,

2 gives 64, 3 gives 96 etc...etc...etc