I am carrying out a project to finalize a project for the college which consists of the following.

An automatic serial number of two groups with numbers with a space in the middle of the third digit (ex: 159 023)

ex: 159 023
159 024
159 025

Thanks for the help.

If you are starting this database from scratch, set your Primary Key (type number) to a serial number (on creation) starting at 159 000 (or whatever starting number you need). From then on each new serial number will have that space between the first 3 digits and the last 3 digits. If you already have many records,  create a calculation (number) field with this definition:

Left ( yourSerialNumberField  ; 3 ) & " " & Right (yourSerialNumberField ; 3 )

You can use this second field with a space between the first 3 and last 3 for your project.

Edited June 14, 20205 yr by Al Quimby

Quote

 

Replace ( yourSerialNumberField; Length(yourSerialNumberField)-2; 0 ; " ")