Jump to content

Running count in a relationship


This topic is 7415 days old. Please don't post here. Open a new topic instead.

Recommended Posts

Can I create a calculation that will give me a running count of the number of records in a self-join relationship?

For example, I have a db with 10 records, and a field called TxnNum. The first four records have a TxnNum of 1. The next 4 have a TxnNum of 2. The last 2 have a TxnNum of 3. I'd like to get a running count so that the records would be enumerated within the TxnNum = TxnNum relationship. The TxnNum, RunningCount pairs would be:

1 , 1

1 , 2

1 , 3

1 , 4

2 , 1

2 , 2

2 , 3

2 , 4

3 , 1

3 , 2

Can I do this?

Thanks,

Dan

Link to comment
Share on other sites

Hi Dan,

There are in fact several ways for this.

You could have the "remainder" (1 to 4) auto-entered from a lookup, and then calculated.

This was discussed a while back. Have a search for "enter from previous"

Do you have an order (sort) for this ?

If not, you could also base your calc upon the value list item function, returning each Ids, where the remainder would be a wordcount of these Ids..

i.e. WordCount(Left(ValueListItems(Status(CurrentFileName), "YourIdsList"), Position(ValueListItems(Status(CurrentFileName), "YourIdsList"), ID, 0, 1)))

if your Ids are built using a "ID"&Left("0000"&serial,4) for example

Link to comment
Share on other sites

This topic is 7415 days old. Please don't post here. Open a new topic instead.

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now
×
×
  • Create New...

Important Information

By using this site, you agree to our Terms of Use.