March 5, 200124 yr i need to find how many field begin by "dem" (dem 1;dem 2;dem 3...) i dont want to use the find mode can you help me
March 5, 200124 yr I don't know of any way to perform a find... Perhaps it's possible to create a self-join using a match with "dem" as the key...
March 5, 200124 yr How about a calculated field: DemCount (calculation, number) = Left(Field1, 3) = "dem" + Left(Field2, 3) = "dem" + Left(Field3, 3) = "dem" . . . This assumes you really mean how many Fields in a given Record contain "dem", not how many records or records and fields contain "dem". It also looks at the data in field, not the field names. -bd
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