Manstone Posted August 17, 2005 Posted August 17, 2005 Hello, Is there anybody can help me to convert a time 34:23:10 (hh:mm:ss) in 1 day 12 hours 23 minutes and 10 seconds? Many thanks for your tips! Dom
comment Posted August 17, 2005 Posted August 17, 2005 That would be extremely difficult. However, if you are willing to accept 1 day 10 hours 23 minutes and 10 seconds as the result, try something like: Let ( [ d = Div ( theTime ; 86400 ) ; r = Mod ( theTime ; 86400 ) ] ; d & " day/s " & Hour ( r ) & " hour/s " & Minute ( r ) & " minute/s " & Seconds ( r ) & " second/s " )
Manstone Posted August 18, 2005 Author Posted August 18, 2005 Thanks. It works perfectly. Sorry for the mistake about the total of hours. I just add a function If for putting the s when there's more than one day, hour, minute and/or second.
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