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format list of numbers


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Try something like:

LeadifyList ( list )

Let ( [

item = LeftValues ( list ; 1 ) ;

processed = Right ( "000" & Substitute ( item; ¶ ; "" ) ; 3 ) ;

nextList = RightValues ( list ; ValueCount ( list ) - 1 )

] ;

Case ( not IsEmpty ( item ) ; processed & ¶ )

&

Case ( not IsEmpty ( nextList ) ; LeadifyList ( nextList ) )

)

It could be simplified a bit by using the new GetValue () function, but this way it's compatible with v.7.

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