RectCount ( pieceA ; pieceB ; materialA ; materialB )

Name & Parameters: [color:red][big] RectCount ( pieceA ; pieceB ; materialA ; materialB ) [/big]

Description: Returns the number of rectangles (with dimensions PieceA x PieceB,) that can be cut from an area of materials (with dimensions MaterialA x MaterialB.

Sample Input:

RectCount(20;30;40;80)

Results:

5

Recursive: yes

Formula:

//RectCount ( pieceA ; pieceB ; materialA; materialB )



/*

Returns the number of rectangles (with dimensions PieceA x PieceB,) that can be cut from an area of materials (with dimensions MaterialA x MaterialB.)



Sub function of: RectCoordinatesSub().

CFs Required:  None



10-13-2005

Rev: 7-29-06

By Mike Hackett

*/



Case((materialA * materialB) / (pieceA * pieceB) < 125; 

  Let(

  [

    PieceLongSide = Max(pieceA; pieceB);

    PieceShortSide = Min(pieceA; pieceB);

    MaterialLongSide = Max(materialA; materialB);

    MaterialShortSide = Min(materialA; materialB;);



    /*Check the count with first cutting hozontal pieces from horizontal material.*/

    CountRows = Case(materialLongSide ≥ pieceLongSide and Div(materialShortSide; pieceShortSide)>0; 

                               Div(materialShortSide; pieceShortSide) + 

                                    RectCount(pieceA; pieceB; materialShortSide; materialLongSide - pieceLongSide));



    /*Check the count with first cutting vertical pieces from horizontal material.*/

    CountColumns = Case(materialShortSide ≥ pieceLongSide and Div(materialLongSide; pieceShortSide)>0; 

                               Div(materialLongSide; pieceShortSide) + 

                                    RectCount(pieceA; pieceB; materialLongSide; materialShortSide - pieceLongSide))

  ];



  /*Return the greater count*/

  Max(countrows; countcolumns)

  );

  "Too many pieces to calculate."

) 

Required Functions:

Author(s) Ender

Date: 07/29/06

Credits: Based on the discussion in this thread: http://www.fmforums.com/forum/showtopic.php?tid/170643/

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