omit Duplicates not working

[Robbydobbs]

I have written a script to omit duplicate records, but for some reason it is not working correctly. What I want it to do is do a find on the field [invoice_id] and omit empty records and then omit any duplicate invoice_id's in the list. This is my script:

Enter Find Mode

set field [invoice_id, "*"]

perform Find

Perform [sort]

go to record [First]

set field [g_invoiceid, invoice_id]

loop

if [g_invoiceid = invoice_id]

omit record

go to record [next, exit after last]

Else

set field [g_invoiceid, invoice_id]

end if

end loop

What's happening is that it omits the records even if they don't have duplicates. It omit every other records plus the duplicates. Could someone help me out and tell me what I did wrong?

[EddyB]

Hi,

Your script will automatically delete the first record so this is where your problem starts

You have set the global field to the invoice_id of the first record, then the next step checks to see if the global = the id, and omits if it does, therefore the first record is omitted.

You need to add in got to next record.

Enter Find Mode

set field [invoice_id, "*"]

perform Find

Perform [sort]

go to record [First]

set field [g_invoiceid, invoice_id]

go to record [next] *****<<<ADD THIS LINE

loop

if [g_invoiceid = invoice_id]

omit record

go to record [next, exit after last]

Else

set field [g_invoiceid, invoice_id]

end if

end loop

Ed.

[Fitch]

Go to next record has to come AFTER the Else in your script.

[Robbydobbs]

Thank you Fitch. I appreciate you clearing that up.