August 7, 200322 yr Does anybody have a good validation calculation for email address, a bit better than this one: If(PatternCount(email, " "),0, 1) Cheers, Huw.
August 7, 200322 yr Hey Huw, I thought about this one and it seems hard to do this in one calculation. You could quit easily check on the @ and . But I'd rather script this and have the entry via a 'custom dialog' followed by a set of 'check'-steps. Regards, Ernst.
August 7, 200322 yr From a post by AndriesV two years ago (and cleaned up a bit): If(IsEmpty(EmailField), 1, Case( PatternCount(EmailField," "), 0, PatternCount(EmailField,","), 0, PatternCount(EmailField,";"), 0, PatternCount(EmailField,":"), 0, PatternCount(EmailField,"
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