mathematically simplify?

[rivet]

I am looking for a simple elegant calc that when the max number is hit it, calc 1

 

'Long' method:  if ( current# + 1 = 4 ; 1 ; current#+1)

 

simple enough I know, but I am guessing there is a cleaner mathematical answer.

[eos]

Check out Mod () – you'd use it to calculate an overshoot (i.e. the relative position) within a cyclic movement, so you could massage the max number to get the desired result.

[jbante]

What you have is fine, actually. Since you're calculation loops between 1 and 3, but the Mod function will reset you back to 0, that wont necessarily be any simpler:

 

Min ( Mod ( $currentNumber + 1 ; 4 ) ; 1 )

 

... unless your application can be modified to use the numbers from 0-2 instead of 1-3, in which case you could use Mod ( $currentNumber + 1 ; 3 )

[rivet]

unless your application can be modified to use the numbers from 0-2 instead of 1-3, in which case you could use Mod ( $currentNumber + 1 ; 3 )

 

Perfect... I have adjusted the object names. Thanks for the help.