Replace a Comma and Space With Carriage Return?

[Dr Kyle]

I have one field in a table which has many different values (text) separated by commas and a space. In order to be able to search each value in that field seperately, I need to replace the comma and space with a carriage return.

Thus, instead of seeing:

Dog, Cat, Rabbit

I need to use find/replace to give me:

Dog

Cat

Rabbit

Can anyone tell me how to do this?

[mr_vodka]

You can write a loop script to do this, but if you want to do this only like one time then you can do a simple 'Replace Field Contents' by clicking in the field and then going into the Record Menu. Replace by calculation.

Substitute ( TrimAll (FieldA; 1 ; 3 ); ","; ¶)

[comment]

Just a note about TrimAll() parameters:

The first parameter, trimSpaces, can be 0. You only need to set trimSpaces to 1 when you're dealing with text containing both Roman and CJK characters. "CJK" is Chinese, Korean and Japanese. "Roman" is everything else.

The second parameter, trimType, should also be 0 in this case. Setting trimType to 3 will remove ALL spaces in the text. For example, the above formula will take "Rabid Dog, Cat, White Rabbit" and return "RabidDog¶Cat¶WhiteRabbit".

[Dr Kyle]

Thanx guys... It worked perfectly!

KYLE