Validating that a Variable is present

[James Gill]

I am trying to validate a variable in a script I created. I want the script to skip over the variable to an else statement if the variable is not valid but neither the if(NotValid) or if(IsEmpty) script steps are getting me the result I want.

Is there something else I need to know about validating with variables?

Edited March 2, 2010 by Guest

[bcooney]

Let's say you set $var = 1.

Then:

If [ not isempty ( $var) ]

do this stuff

else

do other stuff

endif

should work. In fact, you could probably just say if ($var).

[James Gill]

Unfortunately I can't simply match the variable name because it is dependent upon the logged in users username. For some reason the if [not isempty ($var) ] still doesn't work correctly, but I came up with Case (not(IsEmpty($$path));True;False) = "0" that returns a 1 and 0 when the variable is present and not present and this seems to get the job done.

Edited March 3, 2010 by Guest

[comment]

Case (not(IsEmpty($$path));True;False) = "0"

is a very elaborate way to write:

IsEmpty ( $$path )