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Maximum Recursions Limit


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I can confirm that this is the limit.

Starting with a parameter of 1.

Case( num = 10000; "end"; num & " - " & test(num + 1) )

works, but

Case( num = 10001; "end"; num & " - " & test(num + 1) )

returns a question mark.

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I can confirm that this is the limit.

Starting with a parameter of 1.

Case( num = 10000; "end"; num & " - " & test(num + 1) )

works, but

Case( num = 10001; "end"; num & " - " & test(num + 1) )

returns a question mark.

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I can confirm that this is the limit.

Starting with a parameter of 1.

Case( num = 10000; "end"; num & " - " & test(num + 1) )

works, but

Case( num = 10001; "end"; num & " - " & test(num + 1) )

returns a question mark.

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Thanks for confirming, Fenton and JT.

A recursive calculation must provide a mechanism to end the loop, or it will run for 10,000 iterations

That's not very well put, is it? JT's calc clearly does provide such a mechanism (as does mine). It seems that the correct statement would be:

A recursive calculation will run for 10,000 iterations, or until FileMaker runs out of memory, or when a condition to end the loop has been met - whichever of the three comes first.

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Thanks for confirming, Fenton and JT.

A recursive calculation must provide a mechanism to end the loop, or it will run for 10,000 iterations

That's not very well put, is it? JT's calc clearly does provide such a mechanism (as does mine). It seems that the correct statement would be:

A recursive calculation will run for 10,000 iterations, or until FileMaker runs out of memory, or when a condition to end the loop has been met - whichever of the three comes first.

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Thanks for confirming, Fenton and JT.

A recursive calculation must provide a mechanism to end the loop, or it will run for 10,000 iterations

That's not very well put, is it? JT's calc clearly does provide such a mechanism (as does mine). It seems that the correct statement would be:

A recursive calculation will run for 10,000 iterations, or until FileMaker runs out of memory, or when a condition to end the loop has been met - whichever of the three comes first.

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Share on other sites

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