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Claris Engage 2025 - March 25-26 Austin Texas ×

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Posted (edited)

Well, the 3rd friday will always land between the 15th and the 21st (inclusive). Now, you can calculate the correct date based on what day the first of the month is with this sort of scripting:


Date ( MonthNum; 21 - Mod(DayOfWeek( Date(MonthNum;1;2008)); 7); 2008)

Where MonthNum is a field with the number of the month you want in it. Check the attached file for an example.

test.zip

Edited by Guest
Added Example File
Posted

Well, here is another option which eliminates hard coding at all:

Let ( [

m = Month ( date ) ;

y = Year ( date ) ;

d = Date ( m ; 1 ; y )

] ;

d - Mod ( d ; 7 ) - 2 + 21

)

  • 2 years later...
Posted

Well, here is another option which eliminates hard coding at all:

Let ( [

m = Month ( date ) ;

y = Year ( date ) ;

d = Date ( m ; 1 ; y )

] ;

d - Mod ( d ; 7 ) - 2 + 21

)

Something strange here.

It calculates fine except January 2011. When I put any date in January the formula tells that the 3rd Friday in January,11 is January, 14 2011. But it's the 2nd Friday.

Does somebody know why?

This topic is 5052 days old. Please don't post here. Open a new topic instead.

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