Remove last 3 Charecters and Replace with 3 New

[Baylah]

Hi Everyone....Happy holidays...

I can use some help if someone is available.

I need a script that will trim the last 3 letters from a string of text in a specified field and replace them with 3 letters from a target field.

It will always be 3 letters and it will always be the last three letters that need need to be swapped.

Any help would be greatly appreciated.

Thanks,

Steve

[mr_vodka]

If [ Length ( YourField ) > 2 ]

Set Field [ YourField; Replace( YourField; Length ( YourField ) - 3; 3; Target ) ]

End If

Edited December 13, 2008 by Guest
Fixed misplaced closing parenthesis

[Baylah]

Hey Mister V....

I tried your suggestion and it is sticking the 3 letters I need immediatly after the first letter in the required field.

Here is the field (ControlName) as entered before running the script:

EUROPE-ITALY-Washington-HS-AZ-rdu

The last three letters [rdu] need to be replaced with the letters "nyc" as in the field (Departure).

Below is the result if I run the script as currently entered

EnycPE-ITALY-Washington-HS-AZ-rdu

If[(Length(ControlName)>2)]

Set Field [ControlName;

Replace( ControlName; Length ( ControlName-3 ); 3; DEP_Itin_1)

Have I made a mistake here? The result should look like this:

EUROPE-ITALY-Washington-HS-AZ-nyc

Thanks for your help...It is very much appreciated.

Steve

[mr_vodka]

Sorry try it now. I misplaced the closing paranthesis when typing.

[Baylah]

Hey V...

Sorry but this won;t work either...FM won;t let me closwe the dialog because of the add ( at the end.

Your Code

Replace( YourField; Length ( YourField ) - 3; 3; Target ) )

My Code

Replace( ControlName; Length ( ControlName- 3 ); 3; DEP_Itin_1))

I really appreciate your help.

Steve

[comment]

It should be:

Replace ( ControlName ; Length ( ControlName ) - 2 ; 3 ; DEP_Itin_1 )

or, if you like:

Left ( ControlName ; Length ( ControlName ) - 3 ) & DEP_Itin_1

[Baylah]

Perfect Comment...thank you!