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Double loop


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not sure what to call this but I would like to turn these two arrays:

array1:  A, B, C

array2:  1, 2, 3, 4, 5, 6, 7, 8

 
into this:

1A, 2B, 3C,

4A, 5B, 6C,

7A, 8B

 

Was playing with:  

GetValue ( array2 ; loop  ) &  GetValue ( array1 ; mod ( loop ; ValueCount ( array1 ) )  ) 

Just get stuck on

mod ( 3 ; 3 )

which I can handle with an if statement but would rather let math solve it.

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It works with Zero indexed arrays... So your second half should be  ... &  GetValue(array1; (mod(loop-1;valueCount(array1))+1) 

 

loop -1 will simulate zero index array and give you the correct result if you do some shifting:

mod(0;3) = 0 ->add 1 to get 1 (a)

mod(1;3)=1 -> 2(B)

mod(2;3)  = 2 >-3©

 

 

Hope this helps.

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Hi Gismo,

 

We have a Code button that will allow you to post your code so that it look likes you intended. it is the <>  above in the Reply to this topic.

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It should appear, along with (Report Blog this, Edit MultiQuote and Quote very light gray in the body.

If you don’t see them, just make a new reply to this post and use the Code button and repost the code in it.

Edited by Lee Smith
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@Lee I don't see it for my first post, but I do see them for my recent post earlier today. Is there a reason for that?  I'll repost my answer below with code brackets.  


Answer: 

GetValue(array1; (mod(loop-1;valueCount(array1))+1) 

It works with Zero indexed arrays... So your second half should be  ... &  GetValue(array1; (mod(loop-1;valueCount(array1))+1) 

 

loop -1 will simulate zero index array and give you the correct result if you do some shifting:

mod(0;3) = 0 ->add 1 to get 1 (a)

mod(1;3)=1 -> 2( :cool:

mod(2;3)  = 2 >-3©

 

 

Hope this helps.

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@Lee I don't see it for my first post, but I do see them for my recent post earlier today. Is there a reason for that?

"

I think there is a time limit for members to edit their post.

My guess is 24 hours, and or if there has been replies to your post.

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